113433121 has 2 divisors, whose sum is σ = 113433122. Its totient is φ = 113433120.

The previous prime is 113433119. The next prime is 113433127. The reversal of 113433121 is 121334311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101606400 + 11826721 = 10080^2 + 3439^2 .

It is a cyclic number.

It is not a de Polignac number, because 113433121 - 2¹ = 113433119 is a prime.

Together with 113433119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (113433127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716560 + 56716561.

It is an arithmetic number, because the mean of its divisors is an integer number (56716561).

Almost surely, 2^113433121 is an apocalyptic number.

It is an amenable number.

113433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433121 is an equidigital number, since it uses as much as digits as its factorization.

113433121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 19.

The square root of 113433121 is about 10650.4986268249. The cubic root of 113433121 is about 484.0757130035.

Adding to 113433121 its reverse (121334311), we get a palindrome (234767432).

The spelling of 113433121 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred twenty-one".