11343650242140 has 72 divisors (see below), whose sum is σ = 34671737148048. Its totient is φ = 3001881991680.

The previous prime is 11343650242091. The next prime is 11343650242151. The reversal of 11343650242140 is 4124205634311.

11343650242140 is a `hidden beast` number, since 1 + 1 + 3 + 4 + 3 + 6 + 502 + 4 + 2 + 140 = 666.

11343650242140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 11343650242095 and 11343650242104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 240511837 + ... + 240558996.

It is an arithmetic number, because the mean of its divisors is an integer number (481551904834).

Almost surely, 2^{11343650242140} is an apocalyptic number.

11343650242140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11343650242140 is an abundant number, since it is smaller than the sum of its proper divisors (23328086905908).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11343650242140 is a wasteful number, since it uses less digits than its factorization.

11343650242140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 481070979 (or 481070974 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 11343650242140 its reverse (4124205634311), we get a palindrome (15467855876451).

The spelling of 11343650242140 in words is "eleven trillion, three hundred forty-three billion, six hundred fifty million, two hundred forty-two thousand, one hundred forty".