Base | Representation |
---|---|
bin | 10101001000010011… |
… | …11110011101010111 |
3 | 1002021120202120112221 |
4 | 22210021332131113 |
5 | 141213031410033 |
6 | 5113353323211 |
7 | 551054343421 |
oct | 124411763527 |
9 | 32246676487 |
10 | 11344013143 |
11 | 48a1443a81 |
12 | 2247106507 |
13 | 10ba295818 |
14 | 79885d811 |
15 | 465d9412d |
hex | 2a427e757 |
11344013143 has 16 divisors (see below), whose sum is σ = 12078236160. Its totient is φ = 10637272800.
The previous prime is 11344013129. The next prime is 11344013171. The reversal of 11344013143 is 34131044311.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11344013143 - 25 = 11344013111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11344013543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96838 + ... + 179068.
It is an arithmetic number, because the mean of its divisors is an integer number (754889760).
Almost surely, 211344013143 is an apocalyptic number.
11344013143 is a deficient number, since it is larger than the sum of its proper divisors (734223017).
11344013143 is an equidigital number, since it uses as much as digits as its factorization.
11344013143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82398.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11344013143 its reverse (34131044311), we get a palindrome (45475057454).
The spelling of 11344013143 in words is "eleven billion, three hundred forty-four million, thirteen thousand, one hundred forty-three".
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