Base | Representation |
---|---|
bin | 10101001000010011… |
… | …11110011101010110 |
3 | 1002021120202120112220 |
4 | 22210021332131112 |
5 | 141213031410032 |
6 | 5113353323210 |
7 | 551054343420 |
oct | 124411763526 |
9 | 32246676486 |
10 | 11344013142 |
11 | 48a1443a80 |
12 | 2247106506 |
13 | 10ba295817 |
14 | 79885d810 |
15 | 465d9412c |
hex | 2a427e756 |
11344013142 has 32 divisors (see below), whose sum is σ = 28286371584. Its totient is φ = 2946496800.
The previous prime is 11344013129. The next prime is 11344013171. The reversal of 11344013142 is 24131044311.
It is a super-4 number, since 4×113440131424 (a number of 41 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12276609 + ... + 12277532.
It is an arithmetic number, because the mean of its divisors is an integer number (883949112).
Almost surely, 211344013142 is an apocalyptic number.
11344013142 is an abundant number, since it is smaller than the sum of its proper divisors (16942358442).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11344013142 is a wasteful number, since it uses less digits than its factorization.
11344013142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24554164.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 11344013142 its reverse (24131044311), we get a palindrome (35475057453).
The spelling of 11344013142 in words is "eleven billion, three hundred forty-four million, thirteen thousand, one hundred forty-two".
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