11344332031 has 2 divisors, whose sum is σ = 11344332032. Its totient is φ = 11344332030.

The previous prime is 11344332029. The next prime is 11344332133. The reversal of 11344332031 is 13023344311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11344332031 - 2¹ = 11344332029 is a prime.

It is a super-2 number, since 2×11344332031² (a number of 21 digits) contains 22 as substring.

Together with 11344332029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11344331987 and 11344332005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11344330031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672166015 + 5672166016.

It is an arithmetic number, because the mean of its divisors is an integer number (5672166016).

Almost surely, 2^11344332031 is an apocalyptic number.

11344332031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11344332031 is an equidigital number, since it uses as much as digits as its factorization.

11344332031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11344332031 its reverse (13023344311), we get a palindrome (24367676342).

The spelling of 11344332031 in words is "eleven billion, three hundred forty-four million, three hundred thirty-two thousand, thirty-one".