Base | Representation |
---|---|
bin | 10101001000010110… |
… | …11111011110011111 |
3 | 1002021121111202122212 |
4 | 22210023133132133 |
5 | 141213132114102 |
6 | 5113410031035 |
7 | 551060620112 |
oct | 124413373637 |
9 | 32247452585 |
10 | 11344410527 |
11 | 48a169559a |
12 | 224727847b |
13 | 10ba3a4668 |
14 | 798924579 |
15 | 465e21c52 |
hex | 2a42df79f |
11344410527 has 2 divisors, whose sum is σ = 11344410528. Its totient is φ = 11344410526.
The previous prime is 11344410521. The next prime is 11344410529. The reversal of 11344410527 is 72501444311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11344410527 - 26 = 11344410463 is a prime.
Together with 11344410529, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11344410493 and 11344410502.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344410521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672205263 + 5672205264.
It is an arithmetic number, because the mean of its divisors is an integer number (5672205264).
Almost surely, 211344410527 is an apocalyptic number.
11344410527 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344410527 is an equidigital number, since it uses as much as digits as its factorization.
11344410527 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 11344410527 its reverse (72501444311), we get a palindrome (83845854838).
The spelling of 11344410527 in words is "eleven billion, three hundred forty-four million, four hundred ten thousand, five hundred twenty-seven".
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