113444431 has 2 divisors, whose sum is σ = 113444432. Its totient is φ = 113444430.

The previous prime is 113444413. The next prime is 113444437. The reversal of 113444431 is 134444311.

Together with previous prime (113444413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (134444311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113444431 - 2⁵ = 113444399 is a prime.

It is a super-2 number, since 2×113444431² = 25739277849827522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113444396 and 113444405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113444437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56722215 + 56722216.

It is an arithmetic number, because the mean of its divisors is an integer number (56722216).

Almost surely, 2^113444431 is an apocalyptic number.

113444431 is a deficient number, since it is larger than the sum of its proper divisors (1).

113444431 is an equidigital number, since it uses as much as digits as its factorization.

113444431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 25.

The square root of 113444431 is about 10651.0295746468. The cubic root of 113444431 is about 484.0918009395.

Adding to 113444431 its reverse (134444311), we get a palindrome (247888742).

The spelling of 113444431 in words is "one hundred thirteen million, four hundred forty-four thousand, four hundred thirty-one".