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113444437 is a prime number
BaseRepresentation
bin1101100001100…
…00011001010101
321220110120111211
412300300121111
5213020210222
615131301421
72545155541
oct660603125
9256416454
10113444437
1159044537
1231baa871
131a6700b2
14110d0a21
159e5d277
hex6c30655

113444437 has 2 divisors, whose sum is σ = 113444438. Its totient is φ = 113444436.

The previous prime is 113444431. The next prime is 113444489. The reversal of 113444437 is 734444311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92275236 + 21169201 = 9606^2 + 4601^2 .

It is a cyclic number.

It is not a de Polignac number, because 113444437 - 211 = 113442389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113444399 and 113444408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113444431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56722218 + 56722219.

It is an arithmetic number, because the mean of its divisors is an integer number (56722219).

Almost surely, 2113444437 is an apocalyptic number.

It is an amenable number.

113444437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113444437 is an equidigital number, since it uses as much as digits as its factorization.

113444437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 16128, while the sum is 31.

The square root of 113444437 is about 10651.0298563097. The cubic root of 113444437 is about 484.0918094739.

Adding to 113444437 its reverse (734444311), we get a palindrome (847888748).

The spelling of 113444437 in words is "one hundred thirteen million, four hundred forty-four thousand, four hundred thirty-seven".