Base | Representation |
---|---|
bin | 1010010100111010101000… |
… | …0001100100000101100000 |
3 | 1111012110211012221011222221 |
4 | 2211032222001210011200 |
5 | 2442012403440200000 |
6 | 40052055100440424 |
7 | 2251221611625451 |
oct | 245165201440540 |
9 | 44173735834887 |
10 | 11354451100000 |
11 | 36884396aa5a8 |
12 | 133469a849114 |
13 | 644949207658 |
14 | 2b37b6225128 |
15 | 14a54e38c61a |
hex | a53aa064160 |
11354451100000 has 72 divisors (see below), whose sum is σ = 27940806423936. Its totient is φ = 4541780400000.
The previous prime is 11354451099997. The next prime is 11354451100007. The reversal of 11354451100000 is 115445311.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11354451100007) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56672256 + ... + 56872255.
It is an arithmetic number, because the mean of its divisors is an integer number (388066755888).
Almost surely, 211354451100000 is an apocalyptic number.
11354451100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11354451100000 is an abundant number, since it is smaller than the sum of its proper divisors (16586355323936).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11354451100000 is an frugal number, since it uses more digits than its factorization.
11354451100000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113544546 (or 113544518 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11354451100000 its reverse (115445311), we get a palindrome (11354566545311).
The spelling of 11354451100000 in words is "eleven trillion, three hundred fifty-four billion, four hundred fifty-one million, one hundred thousand".
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