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11355043200181 is a prime number
BaseRepresentation
bin1010010100111100110101…
…0100001111110010110101
31111012112100111001222202021
42211033031110033302311
52442020112024401211
640052233531313141
72251242361453162
oct245171524176265
944175314058667
1011355043200181
11368871295219a
121334824bab7b1
13644a11a985a5
142b3830b13069
1514a586349771
hexa53cd50fcb5

11355043200181 has 2 divisors, whose sum is σ = 11355043200182. Its totient is φ = 11355043200180.

The previous prime is 11355043200001. The next prime is 11355043200209. The reversal of 11355043200181 is 18100234055311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10583368797681 + 771674402500 = 3253209^2 + 878450^2 .

It is a cyclic number.

It is not a de Polignac number, because 11355043200181 - 229 = 11354506329269 is a prime.

It is a super-2 number, since 2×113550432001812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11355043240181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677521600090 + 5677521600091.

It is an arithmetic number, because the mean of its divisors is an integer number (5677521600091).

Almost surely, 211355043200181 is an apocalyptic number.

It is an amenable number.

11355043200181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11355043200181 is an equidigital number, since it uses as much as digits as its factorization.

11355043200181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 11355043200181 its reverse (18100234055311), we get a palindrome (29455277255492).

The spelling of 11355043200181 in words is "eleven trillion, three hundred fifty-five billion, forty-three million, two hundred thousand, one hundred eighty-one".