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11360416127 is a prime number
BaseRepresentation
bin10101001010010001…
…00011000101111111
31002022201121221012212
422211020203011333
5141231231304002
65115141051035
7551343641504
oct124510430577
932281557185
1011360416127
1148aa727865
1222506b6a7b
1310c07b9928
1479aacd4ab
15467534352
hex2a522317f

11360416127 has 2 divisors, whose sum is σ = 11360416128. Its totient is φ = 11360416126.

The previous prime is 11360416061. The next prime is 11360416129. The reversal of 11360416127 is 72161406311.

11360416127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (72161406311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11360416127 - 210 = 11360415103 is a prime.

Together with 11360416129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11360416093 and 11360416102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11360416129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5680208063 + 5680208064.

It is an arithmetic number, because the mean of its divisors is an integer number (5680208064).

Almost surely, 211360416127 is an apocalyptic number.

11360416127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11360416127 is an equidigital number, since it uses as much as digits as its factorization.

11360416127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

The spelling of 11360416127 in words is "eleven billion, three hundred sixty million, four hundred sixteen thousand, one hundred twenty-seven".