Base | Representation |
---|---|
bin | 110100111100011000… |
… | …0111101000101101110 |
3 | 101212110121200001200220 |
4 | 1221320300331011232 |
5 | 3330321440430000 |
6 | 124121511432210 |
7 | 11133321445266 |
oct | 1517060750556 |
9 | 355417601626 |
10 | 113695248750 |
11 | 442440051a6 |
12 | 1a050385666 |
13 | a94bc49025 |
14 | 5707c887a6 |
15 | 2e567211a0 |
hex | 1a78c3d16e |
113695248750 has 40 divisors (see below), whose sum is σ = 284147175048. Its totient is φ = 30318732000.
The previous prime is 113695248713. The next prime is 113695248767. The reversal of 113695248750 is 57842596311.
It is a junction number, because it is equal to n+sod(n) for n = 113695248693 and 113695248702.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 15155617 + ... + 15163116.
It is a 1-persistent number, because it is pandigital, but 2⋅113695248750 = 227390497500 is not.
Almost surely, 2113695248750 is an apocalyptic number.
113695248750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113695248750 is an abundant number, since it is smaller than the sum of its proper divisors (170451926298).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113695248750 is an equidigital number, since it uses as much as digits as its factorization.
113695248750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30318758 (or 30318743 counting only the distinct ones).
The product of its (nonzero) digits is 1814400, while the sum is 51.
The spelling of 113695248750 in words is "one hundred thirteen billion, six hundred ninety-five million, two hundred forty-eight thousand, seven hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •