Base | Representation |
---|---|
bin | 11001110111010010000010… |
… | …110010011110101101101111 |
3 | 112220202101220121121121212002 |
4 | 121313102002302132231233 |
5 | 104402140210140411401 |
6 | 1041532024524002515 |
7 | 32650113501662246 |
oct | 3167220262365557 |
9 | 486671817547762 |
10 | 113750108138351 |
11 | 33276171648553 |
12 | 1091164909043b |
13 | 4b61787540ba9 |
14 | 201376ad7b95d |
15 | d23d7c114a6b |
hex | 677482c9eb6f |
113750108138351 has 2 divisors, whose sum is σ = 113750108138352. Its totient is φ = 113750108138350.
The previous prime is 113750108138347. The next prime is 113750108138353. The reversal of 113750108138351 is 153831801057311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113750108138351 - 22 = 113750108138347 is a prime.
Together with 113750108138353, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 113750108138296 and 113750108138305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113750108138353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56875054069175 + 56875054069176.
It is an arithmetic number, because the mean of its divisors is an integer number (56875054069176).
Almost surely, 2113750108138351 is an apocalyptic number.
113750108138351 is a deficient number, since it is larger than the sum of its proper divisors (1).
113750108138351 is an equidigital number, since it uses as much as digits as its factorization.
113750108138351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 47.
The spelling of 113750108138351 in words is "one hundred thirteen trillion, seven hundred fifty billion, one hundred eight million, one hundred thirty-eight thousand, three hundred fifty-one".
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