Base | Representation |
---|---|
bin | 10000100101101101010… |
… | …010111011101110111111 |
3 | 11000222112120010222101212 |
4 | 100211231102323232333 |
5 | 122134210000410442 |
6 | 2231413032355035 |
7 | 145235156141654 |
oct | 20455522735677 |
9 | 4028476128355 |
10 | 1140000013247 |
11 | 3aa520318a87 |
12 | 164b33845a7b |
13 | 83669b63874 |
14 | 3d267a79c2b |
15 | 1e9c248ba82 |
hex | 1096d4bbbbf |
1140000013247 has 2 divisors, whose sum is σ = 1140000013248. Its totient is φ = 1140000013246.
The previous prime is 1140000013181. The next prime is 1140000013249. The reversal of 1140000013247 is 7423100000411.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (7423100000411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1140000013247 - 228 = 1139731577791 is a prime.
Together with 1140000013249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140000013249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570000006623 + 570000006624.
It is an arithmetic number, because the mean of its divisors is an integer number (570000006624).
Almost surely, 21140000013247 is an apocalyptic number.
1140000013247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140000013247 is an equidigital number, since it uses as much as digits as its factorization.
1140000013247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 1140000013247 its reverse (7423100000411), we get a palindrome (8563100013658).
The spelling of 1140000013247 in words is "one trillion, one hundred forty billion, thirteen thousand, two hundred forty-seven".
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