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114004677145481 is a prime number
BaseRepresentation
bin11001111010111111001000…
…010010001011001110001001
3112221122201222222010002110122
4121322333020102023032021
5104420323034322123411
61042245005313153025
733004365114562433
oct3172771022131611
9487581888102418
10114004677145481
1133364126175451
1210952a5385b775
134b7c7970881a5
142021bda4dd653
15d2a7cb0ed9db
hex67afc848b389

114004677145481 has 2 divisors, whose sum is σ = 114004677145482. Its totient is φ = 114004677145480.

The previous prime is 114004677145451. The next prime is 114004677145483. The reversal of 114004677145481 is 184541776400411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85815118686025 + 28189558459456 = 9263645^2 + 5309384^2 .

It is a cyclic number.

It is not a de Polignac number, because 114004677145481 - 218 = 114004676883337 is a prime.

It is a super-2 number, since 2×1140046771454812 (a number of 29 digits) contains 22 as substring.

Together with 114004677145483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114004677145483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57002338572740 + 57002338572741.

It is an arithmetic number, because the mean of its divisors is an integer number (57002338572741).

Almost surely, 2114004677145481 is an apocalyptic number.

It is an amenable number.

114004677145481 is a deficient number, since it is larger than the sum of its proper divisors (1).

114004677145481 is an equidigital number, since it uses as much as digits as its factorization.

114004677145481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3010560, while the sum is 53.

The spelling of 114004677145481 in words is "one hundred fourteen trillion, four billion, six hundred seventy-seven million, one hundred forty-five thousand, four hundred eighty-one".