Base | Representation |
---|---|
bin | 11001111011000110011101… |
… | …000100101101110100101100 |
3 | 112221200111022002110210000010 |
4 | 121323012131010231310230 |
5 | 104420440141241202000 |
6 | 1042252345551133220 |
7 | 33005064036060015 |
oct | 3173063504556454 |
9 | 487614262423003 |
10 | 114012542131500 |
11 | 333674a18068a1 |
12 | 10954489814210 |
13 | 4b8044b64857c |
14 | 2022344ca000c |
15 | d2aadb829d50 |
hex | 67b19d12dd2c |
114012542131500 has 96 divisors (see below), whose sum is σ = 332542620236736. Its totient is φ = 30354068236800.
The previous prime is 114012542131489. The next prime is 114012542131549. The reversal of 114012542131500 is 5131245210411.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60669607 + ... + 62520606.
It is an arithmetic number, because the mean of its divisors is an integer number (3463985627466).
Almost surely, 2114012542131500 is an apocalyptic number.
114012542131500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114012542131500 is an abundant number, since it is smaller than the sum of its proper divisors (218530078105236).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114012542131500 is a wasteful number, since it uses less digits than its factorization.
114012542131500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123190852 (or 123190840 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 114012542131500 its reverse (5131245210411), we get a palindrome (119143787341911).
The spelling of 114012542131500 in words is "one hundred fourteen trillion, twelve billion, five hundred forty-two million, one hundred thirty-one thousand, five hundred".
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