Base | Representation |
---|---|
bin | 10101001111001000… |
… | …11100100001000101 |
3 | 1002102120112012220221 |
4 | 22213210130201011 |
5 | 141322212034103 |
6 | 5123201024341 |
7 | 552351212014 |
oct | 124744344105 |
9 | 32376465827 |
10 | 11401283653 |
11 | 4920800181 |
12 | 22623250b1 |
13 | 10c90c82b6 |
14 | 7a22caa7b |
15 | 46ae081bd |
hex | 2a791c845 |
11401283653 has 2 divisors, whose sum is σ = 11401283654. Its totient is φ = 11401283652.
The previous prime is 11401283651. The next prime is 11401283681. The reversal of 11401283653 is 35638210411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10498461444 + 902822209 = 102462^2 + 30047^2 .
It is an emirp because it is prime and its reverse (35638210411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11401283653 - 21 = 11401283651 is a prime.
Together with 11401283651, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11401283651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700641826 + 5700641827.
It is an arithmetic number, because the mean of its divisors is an integer number (5700641827).
Almost surely, 211401283653 is an apocalyptic number.
It is an amenable number.
11401283653 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401283653 is an equidigital number, since it uses as much as digits as its factorization.
11401283653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 11401283653 in words is "eleven billion, four hundred one million, two hundred eighty-three thousand, six hundred fifty-three".
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