Base | Representation |
---|---|
bin | 1010010111101100001011… |
… | …1001101101111111100111 |
3 | 1111101000211212102100212221 |
4 | 2211323002321231333213 |
5 | 2443303011424122322 |
6 | 40130020343053211 |
7 | 2254526664230653 |
oct | 245730271557747 |
9 | 44330755370787 |
10 | 11402113114087 |
11 | 36a6677667193 |
12 | 1341980741207 |
13 | 6492a3792357 |
14 | 2b5c18239a63 |
15 | 14b8dd85a9c7 |
hex | a5ec2e6dfe7 |
11402113114087 has 2 divisors, whose sum is σ = 11402113114088. Its totient is φ = 11402113114086.
The previous prime is 11402113114081. The next prime is 11402113114141. The reversal of 11402113114087 is 78041131120411.
It is a weak prime.
It is an emirp because it is prime and its reverse (78041131120411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11402113114087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11402113114081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701056557043 + 5701056557044.
It is an arithmetic number, because the mean of its divisors is an integer number (5701056557044).
Almost surely, 211402113114087 is an apocalyptic number.
11402113114087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402113114087 is an equidigital number, since it uses as much as digits as its factorization.
11402113114087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 34.
Adding to 11402113114087 its reverse (78041131120411), we get a palindrome (89443244234498).
The spelling of 11402113114087 in words is "eleven trillion, four hundred two billion, one hundred thirteen million, one hundred fourteen thousand, eighty-seven".
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