Search a number
-
+
11402113114141 is a prime number
BaseRepresentation
bin1010010111101100001011…
…1001101110000000011101
31111101000211212102100221221
42211323002321232000131
52443303011424123031
640130020343053341
72254526664231061
oct245730271560035
944330755370857
1011402113114141
1136a6677667232
121341980741251
136492a3792399
142b5c18239aa1
1514b8dd85aa11
hexa5ec2e6e01d

11402113114141 has 2 divisors, whose sum is σ = 11402113114142. Its totient is φ = 11402113114140.

The previous prime is 11402113114087. The next prime is 11402113114177. The reversal of 11402113114141 is 14141131120411.

11402113114141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6292496995225 + 5109616118916 = 2508485^2 + 2260446^2 .

It is a cyclic number.

It is not a de Polignac number, because 11402113114141 - 213 = 11402113105949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11402113114541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701056557070 + 5701056557071.

It is an arithmetic number, because the mean of its divisors is an integer number (5701056557071).

Almost surely, 211402113114141 is an apocalyptic number.

It is an amenable number.

11402113114141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402113114141 is an equidigital number, since it uses as much as digits as its factorization.

11402113114141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 11402113114141 its reverse (14141131120411), we get a palindrome (25543244234552).

The spelling of 11402113114141 in words is "eleven trillion, four hundred two billion, one hundred thirteen million, one hundred fourteen thousand, one hundred forty-one".