Base | Representation |
---|---|
bin | 11001111011010111000110… |
… | …000110000111111010011111 |
3 | 112221202012102100110111210122 |
4 | 121323113012012013322133 |
5 | 104421233240010014201 |
6 | 1042304503002425155 |
7 | 33006265603333565 |
oct | 3173270606077237 |
9 | 487665370414718 |
10 | 114030410235551 |
11 | 333740308a1937 |
12 | 10957a358021bb |
13 | 4b820384483c4 |
14 | 202315bd95a35 |
15 | d2b2d532ce1b |
hex | 67b5c6187e9f |
114030410235551 has 2 divisors, whose sum is σ = 114030410235552. Its totient is φ = 114030410235550.
The previous prime is 114030410235541. The next prime is 114030410235631. The reversal of 114030410235551 is 155532014030411.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (155532014030411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114030410235551 - 222 = 114030406041247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114030410235541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57015205117775 + 57015205117776.
It is an arithmetic number, because the mean of its divisors is an integer number (57015205117776).
Almost surely, 2114030410235551 is an apocalyptic number.
114030410235551 is a deficient number, since it is larger than the sum of its proper divisors (1).
114030410235551 is an equidigital number, since it uses as much as digits as its factorization.
114030410235551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 114030410235551 its reverse (155532014030411), we get a palindrome (269562424265962).
The spelling of 114030410235551 in words is "one hundred fourteen trillion, thirty billion, four hundred ten million, two hundred thirty-five thousand, five hundred fifty-one".
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