Base | Representation |
---|---|
bin | 11001111011010111000110… |
… | …000110000111111010011110 |
3 | 112221202012102100110111210121 |
4 | 121323113012012013322132 |
5 | 104421233240010014200 |
6 | 1042304503002425154 |
7 | 33006265603333564 |
oct | 3173270606077236 |
9 | 487665370414717 |
10 | 114030410235550 |
11 | 333740308a1936 |
12 | 10957a358021ba |
13 | 4b820384483c3 |
14 | 202315bd95a34 |
15 | d2b2d532ce1a |
hex | 67b5c6187e9e |
114030410235550 has 96 divisors (see below), whose sum is σ = 212974815739392. Its totient is φ = 45423804814080.
The previous prime is 114030410235541. The next prime is 114030410235551. The reversal of 114030410235550 is 55532014030411.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114030410235551) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 37720941339 + ... + 37720944361.
It is an arithmetic number, because the mean of its divisors is an integer number (2218487663952).
Almost surely, 2114030410235550 is an apocalyptic number.
114030410235550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114030410235550 is a deficient number, since it is larger than the sum of its proper divisors (98944405503842).
114030410235550 is a wasteful number, since it uses less digits than its factorization.
114030410235550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6322 (or 6317 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 114030410235550 its reverse (55532014030411), we get a palindrome (169562424265961).
The spelling of 114030410235550 in words is "one hundred fourteen trillion, thirty billion, four hundred ten million, two hundred thirty-five thousand, five hundred fifty".
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