Base | Representation |
---|---|
bin | 10101001111011101… |
… | …10110111100111011 |
3 | 1002102202122220101121 |
4 | 22213232312330323 |
5 | 141323411411441 |
6 | 5123335330111 |
7 | 552413341252 |
oct | 124756667473 |
9 | 32382586347 |
10 | 11404013371 |
11 | 49222a5043 |
12 | 2263220937 |
13 | 10c984290a |
14 | 7a27db799 |
15 | 46b296dd1 |
hex | 2a7bb6f3b |
11404013371 has 2 divisors, whose sum is σ = 11404013372. Its totient is φ = 11404013370.
The previous prime is 11404013297. The next prime is 11404013471. The reversal of 11404013371 is 17331040411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11404013371 - 29 = 11404012859 is a prime.
It is not a weakly prime, because it can be changed into another prime (11404013171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702006685 + 5702006686.
It is an arithmetic number, because the mean of its divisors is an integer number (5702006686).
Almost surely, 211404013371 is an apocalyptic number.
11404013371 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404013371 is an equidigital number, since it uses as much as digits as its factorization.
11404013371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11404013371 its reverse (17331040411), we get a palindrome (28735053782).
The spelling of 11404013371 in words is "eleven billion, four hundred four million, thirteen thousand, three hundred seventy-one".
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