11404013471 has 2 divisors, whose sum is σ = 11404013472. Its totient is φ = 11404013470.

The previous prime is 11404013371. The next prime is 11404013473. The reversal of 11404013471 is 17431040411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11404013471 is a prime.

It is a super-3 number, since 3×11404013471³ (a number of 31 digits) contains 333 as substring.

Together with 11404013473, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11404013471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11404013473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702006735 + 5702006736.

It is an arithmetic number, because the mean of its divisors is an integer number (5702006736).

Almost surely, 2^11404013471 is an apocalyptic number.

11404013471 is a deficient number, since it is larger than the sum of its proper divisors (1).

11404013471 is an equidigital number, since it uses as much as digits as its factorization.

11404013471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 11404013471 its reverse (17431040411), we get a palindrome (28835053882).

The spelling of 11404013471 in words is "eleven billion, four hundred four million, thirteen thousand, four hundred seventy-one".