Base | Representation |
---|---|
bin | 110101000111000011… |
… | …0111100010110011111 |
3 | 101220101120110200220112 |
4 | 1222032012330112133 |
5 | 3332040123200211 |
6 | 124221222440235 |
7 | 11145230230001 |
oct | 1521606742637 |
9 | 356346420815 |
10 | 114053334431 |
11 | 44408152283 |
12 | 1a13029307b |
13 | a9a81a364a |
14 | 573d65c371 |
15 | 2e77da588b |
hex | 1a8e1bc59f |
114053334431 has 2 divisors, whose sum is σ = 114053334432. Its totient is φ = 114053334430.
The previous prime is 114053334401. The next prime is 114053334433. The reversal of 114053334431 is 134433350411.
It is a strong prime.
It is an emirp because it is prime and its reverse (134433350411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114053334431 is a prime.
It is a super-2 number, since 2×1140533344312 (a number of 23 digits) contains 22 as substring.
Together with 114053334433, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114053334433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57026667215 + 57026667216.
It is an arithmetic number, because the mean of its divisors is an integer number (57026667216).
Almost surely, 2114053334431 is an apocalyptic number.
114053334431 is a deficient number, since it is larger than the sum of its proper divisors (1).
114053334431 is an equidigital number, since it uses as much as digits as its factorization.
114053334431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 114053334431 its reverse (134433350411), we get a palindrome (248486684842).
The spelling of 114053334431 in words is "one hundred fourteen billion, fifty-three million, three hundred thirty-four thousand, four hundred thirty-one".
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