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11411020111223 is a prime number
BaseRepresentation
bin1010011000001101010111…
…0011001101110101110111
31111101212211121111200221202
42212003111303031311313
52443424232122024343
640134052243003115
72255263500401435
oct246032563156567
944355747450852
1011411020111223
1136aa428405a47
12134364766949b
1364a092bab965
142b6421161d55
1514bc607b5db8
hexa60d5ccdd77

11411020111223 has 2 divisors, whose sum is σ = 11411020111224. Its totient is φ = 11411020111222.

The previous prime is 11411020111181. The next prime is 11411020111229. The reversal of 11411020111223 is 32211102011411.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (32211102011411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11411020111223 - 210 = 11411020110199 is a prime.

It is a super-2 number, since 2×114110201112232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11411020111195 and 11411020111204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411020111229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705510055611 + 5705510055612.

It is an arithmetic number, because the mean of its divisors is an integer number (5705510055612).

Almost surely, 211411020111223 is an apocalyptic number.

11411020111223 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411020111223 is an equidigital number, since it uses as much as digits as its factorization.

11411020111223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 11411020111223 its reverse (32211102011411), we get a palindrome (43622122122634).

The spelling of 11411020111223 in words is "eleven trillion, four hundred eleven billion, twenty million, one hundred eleven thousand, two hundred twenty-three".