11411419181 has 2 divisors, whose sum is σ = 11411419182. Its totient is φ = 11411419180.

The previous prime is 11411419153. The next prime is 11411419183. The reversal of 11411419181 is 18191411411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8898903556 + 2512515625 = 94334^2 + 50125^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11411419181 is a prime.

It is a super-3 number, since 3×11411419181³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11411419183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411419183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705709590 + 5705709591.

It is an arithmetic number, because the mean of its divisors is an integer number (5705709591).

Almost surely, 2^11411419181 is an apocalyptic number.

It is an amenable number.

11411419181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411419181 is an equidigital number, since it uses as much as digits as its factorization.

11411419181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 32.

The spelling of 11411419181 in words is "eleven billion, four hundred eleven million, four hundred nineteen thousand, one hundred eighty-one".