Base | Representation |
---|---|
bin | 1010011000010001011011… |
… | …1100101110111111100110 |
3 | 1111101222122210012120110110 |
4 | 2212010112330232333212 |
5 | 2443434001430002400 |
6 | 40134352530033450 |
7 | 2255332542020520 |
oct | 246042674567746 |
9 | 44358583176413 |
10 | 11412113125350 |
11 | 36aa939389703 |
12 | 13438b1718886 |
13 | 64a208484992 |
14 | 2b64c63a2a10 |
15 | 14bcc671be50 |
hex | a6116f2efe6 |
11412113125350 has 48 divisors (see below), whose sum is σ = 32345189203968. Its totient is φ = 2608482999840.
The previous prime is 11412113125331. The next prime is 11412113125373. The reversal of 11412113125350 is 5352131121411.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5434338534 + ... + 5434340633.
It is an arithmetic number, because the mean of its divisors is an integer number (673858108416).
Almost surely, 211412113125350 is an apocalyptic number.
11412113125350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11412113125350 is an abundant number, since it is smaller than the sum of its proper divisors (20933076078618).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11412113125350 is a wasteful number, since it uses less digits than its factorization.
11412113125350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10868679189 (or 10868679184 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 11412113125350 its reverse (5352131121411), we get a palindrome (16764244246761).
The spelling of 11412113125350 in words is "eleven trillion, four hundred twelve billion, one hundred thirteen million, one hundred twenty-five thousand, three hundred fifty".
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