Base | Representation |
---|---|
bin | 110101001001000101… |
… | …0001111111100110000 |
3 | 101220120022101012212012 |
4 | 1222102022033330300 |
5 | 3332210023410000 |
6 | 124232051422052 |
7 | 11150014062335 |
oct | 1522212177460 |
9 | 356508335765 |
10 | 114121310000 |
11 | 44442560335 |
12 | 1a14abb4928 |
13 | a9b92b3889 |
14 | 57486b498c |
15 | 2e7dd31735 |
hex | 1a9228ff30 |
114121310000 has 50 divisors (see below), whose sum is σ = 276299127852. Its totient is φ = 45648520000.
The previous prime is 114121309997. The next prime is 114121310027. The reversal of 114121310000 is 13121411.
It is a tau number, because it is divible by the number of its divisors (50).
It is a super-5 number, since 5×1141213100005 (a number of 56 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5696066 + ... + 5716065.
Almost surely, 2114121310000 is an apocalyptic number.
114121310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114121310000 is an abundant number, since it is smaller than the sum of its proper divisors (162177817852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114121310000 is an equidigital number, since it uses as much as digits as its factorization.
114121310000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11412159 (or 11412138 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 114121310000 its reverse (13121411), we get a palindrome (114134431411).
The spelling of 114121310000 in words is "one hundred fourteen billion, one hundred twenty-one million, three hundred ten thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.321 sec. • engine limits •