Base | Representation |
---|---|
bin | 10101010000011110… |
… | …10010000111100111 |
3 | 1002110100122202001010 |
4 | 22220033102013213 |
5 | 141333100411010 |
6 | 5124241433303 |
7 | 552545522253 |
oct | 125017220747 |
9 | 32410582033 |
10 | 11412513255 |
11 | 4927080140 |
12 | 226603b833 |
13 | 10cb52a730 |
14 | 7a39b1263 |
15 | 46bdc5620 |
hex | 2a83d21e7 |
11412513255 has 64 divisors (see below), whose sum is σ = 21951401472. Its totient is φ = 4988874240.
The previous prime is 11412513187. The next prime is 11412513263. The reversal of 11412513255 is 55231521411.
11412513255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11412513255 - 210 = 11412512231 is a prime.
It is a super-3 number, since 3×114125132553 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30369 + ... + 154101.
It is an arithmetic number, because the mean of its divisors is an integer number (342990648).
Almost surely, 211412513255 is an apocalyptic number.
11412513255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11412513255 is a deficient number, since it is larger than the sum of its proper divisors (10538888217).
11412513255 is a wasteful number, since it uses less digits than its factorization.
11412513255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123808.
The product of its digits is 6000, while the sum is 30.
The spelling of 11412513255 in words is "eleven billion, four hundred twelve million, five hundred thirteen thousand, two hundred fifty-five".
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