Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11100100001000000 |
3 | 1002110101222012102221 |
4 | 22220101330201000 |
5 | 141333240224300 |
6 | 5124304420424 |
7 | 552554460136 |
oct | 125021744100 |
9 | 32411865387 |
10 | 11413211200 |
11 | 4927507556 |
12 | 2266317714 |
13 | 10cb713311 |
14 | 7a3b13756 |
15 | 46beb231a |
hex | 2a847c840 |
11413211200 has 42 divisors (see below), whose sum is σ = 28083636746. Its totient is φ = 4565283840.
The previous prime is 11413211189. The next prime is 11413211219. The reversal of 11413211200 is 211231411.
It can be written as a sum of positive squares in 3 ways, for example, as 1692828736 + 9720382464 = 41144^2 + 98592^2 .
It is a super-2 number, since 2×114132112002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3565029 + ... + 3568228.
Almost surely, 211413211200 is an apocalyptic number.
11413211200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11413211200 is an abundant number, since it is smaller than the sum of its proper divisors (16670425546).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11413211200 is an equidigital number, since it uses as much as digits as its factorization.
11413211200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7133279 (or 7133264 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11413211200 its reverse (211231411), we get a palindrome (11624442611).
The spelling of 11413211200 in words is "eleven billion, four hundred thirteen million, two hundred eleven thousand, two hundred".
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