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114300343439 is a prime number
BaseRepresentation
bin110101001110011010…
…1001101010010001111
3101221000210021001120022
41222130311031102033
53333041341442224
6124301525012355
711154316613612
oct1523465152217
9357023231508
10114300343439
1144524622857
121a19ab540bb
13aa17409819
14576439a179
152e8e8e865e
hex1a9cd4d48f

114300343439 has 2 divisors, whose sum is σ = 114300343440. Its totient is φ = 114300343438.

The previous prime is 114300343429. The next prime is 114300343441. The reversal of 114300343439 is 934343003411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114300343439 is a prime.

It is a Sophie Germain prime.

Together with 114300343441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114300343399 and 114300343408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114300343429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150171719 + 57150171720.

It is an arithmetic number, because the mean of its divisors is an integer number (57150171720).

Almost surely, 2114300343439 is an apocalyptic number.

114300343439 is a deficient number, since it is larger than the sum of its proper divisors (1).

114300343439 is an equidigital number, since it uses as much as digits as its factorization.

114300343439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 114300343439 in words is "one hundred fourteen billion, three hundred million, three hundred forty-three thousand, four hundred thirty-nine".