Base | Representation |
---|---|
bin | 10000101000100111010… |
… | …001001101010011011100 |
3 | 11001021121000011222111001 |
4 | 100220213101031103130 |
5 | 122212102222414400 |
6 | 2233050411240044 |
7 | 145405403504104 |
oct | 20504721152334 |
9 | 4037530158431 |
10 | 1143120123100 |
11 | 40088156576a |
12 | 165664749024 |
13 | 83a463b0007 |
14 | 3d4821ca204 |
15 | 1eb06358a6a |
hex | 10a2744d4dc |
1143120123100 has 18 divisors (see below), whose sum is σ = 2480570667344. Its totient is φ = 457248049200.
The previous prime is 1143120123097. The next prime is 1143120123107. The reversal of 1143120123100 is 13210213411.
It is a super-2 number, since 2×11431201231002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1143120123107) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5715600516 + ... + 5715600715.
Almost surely, 21143120123100 is an apocalyptic number.
1143120123100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1143120123100 is an abundant number, since it is smaller than the sum of its proper divisors (1337450544244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1143120123100 is a wasteful number, since it uses less digits than its factorization.
1143120123100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11431201245 (or 11431201238 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1143120123100 its reverse (13210213411), we get a palindrome (1156330336511).
The spelling of 1143120123100 in words is "one trillion, one hundred forty-three billion, one hundred twenty million, one hundred twenty-three thousand, one hundred".
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