Base | Representation |
---|---|
bin | 11001111111110001011001… |
… | …100001011001000010010010 |
3 | 112222211011211101022022212120 |
4 | 121333301121201121002102 |
5 | 104441220033011020132 |
6 | 1043100033232035110 |
7 | 33040216330263642 |
oct | 3177613141310222 |
9 | 488734741268776 |
10 | 114333531345042 |
11 | 3348063a858969 |
12 | 109a6730392a96 |
13 | 4ba47b4a83459 |
14 | 2033ab5828522 |
15 | d34126a0502c |
hex | 67fc59859092 |
114333531345042 has 32 divisors (see below), whose sum is σ = 254861122507200. Its totient is φ = 33981482999808.
The previous prime is 114333531344993. The next prime is 114333531345071. The reversal of 114333531345042 is 240543135333411.
It is a junction number, because it is equal to n+sod(n) for n = 114333531344985 and 114333531345003.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29497813167 + ... + 29497817042.
It is an arithmetic number, because the mean of its divisors is an integer number (7964410078350).
Almost surely, 2114333531345042 is an apocalyptic number.
114333531345042 is an abundant number, since it is smaller than the sum of its proper divisors (140527591162158).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114333531345042 is a wasteful number, since it uses less digits than its factorization.
114333531345042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58995630250.
The product of its (nonzero) digits is 777600, while the sum is 42.
Adding to 114333531345042 its reverse (240543135333411), we get a palindrome (354876666678453).
The spelling of 114333531345042 in words is "one hundred fourteen trillion, three hundred thirty-three billion, five hundred thirty-one million, three hundred forty-five thousand, forty-two".
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