1143423133 has 2 divisors, whose sum is σ = 1143423134. Its totient is φ = 1143423132.

The previous prime is 1143423131. The next prime is 1143423143. The reversal of 1143423133 is 3313243411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 763251129 + 380172004 = 27627^2 + 19498^2 .

It is an emirp because it is prime and its reverse (3313243411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1143423133 - 2¹ = 1143423131 is a prime.

It is a super-2 number, since 2×1143423133² = 2614832922159071378, which contains 22 as substring.

Together with 1143423131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1143423098 and 1143423107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1143423131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571711566 + 571711567.

It is an arithmetic number, because the mean of its divisors is an integer number (571711567).

Almost surely, 2^1143423133 is an apocalyptic number.

It is an amenable number.

1143423133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143423133 is an equidigital number, since it uses as much as digits as its factorization.

1143423133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 25.

The square root of 1143423133 is about 33814.5402600716. The cubic root of 1143423133 is about 1045.6884829121.

Adding to 1143423133 its reverse (3313243411), we get a palindrome (4456666544).

The spelling of 1143423133 in words is "one billion, one hundred forty-three million, four hundred twenty-three thousand, one hundred thirty-three".