1143534113597 has 2 divisors, whose sum is σ = 1143534113598. Its totient is φ = 1143534113596.

The previous prime is 1143534113549. The next prime is 1143534113599. The reversal of 1143534113597 is 7953114353411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 992322791716 + 151211321881 = 996154^2 + 388859^2 .

It is a cyclic number.

It is not a de Polignac number, because 1143534113597 - 2¹⁰ = 1143534112573 is a prime.

Together with 1143534113599, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1143534113599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571767056798 + 571767056799.

It is an arithmetic number, because the mean of its divisors is an integer number (571767056799).

Almost surely, 2^{1143534113597} is an apocalyptic number.

It is an amenable number.

1143534113597 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143534113597 is an equidigital number, since it uses as much as digits as its factorization.

1143534113597 is an evil number, because the sum of its binary digits is even.

The product of its digits is 680400, while the sum is 47.

The spelling of 1143534113597 in words is "one trillion, one hundred forty-three billion, five hundred thirty-four million, one hundred thirteen thousand, five hundred ninety-seven".