Base | Representation |
---|---|
bin | 1010011001110100111110… |
… | …1000010101100100010100 |
3 | 1111111112122000000201120110 |
4 | 2212131033220111210110 |
5 | 2444403212433232122 |
6 | 40154532220403020 |
7 | 2260266652511325 |
oct | 246351750254424 |
9 | 44445560021513 |
10 | 11438833883412 |
11 | 3710200576731 |
12 | 1348b0a3a6470 |
13 | 64c8a6354c20 |
14 | 2b78dd0b644c |
15 | 14c83c4e390c |
hex | a674fa15914 |
11438833883412 has 96 divisors (see below), whose sum is σ = 29288316089088. Its totient is φ = 3452968157184.
The previous prime is 11438833883317. The next prime is 11438833883413. The reversal of 11438833883412 is 21438833883411.
It is a happy number.
It is a super-2 number, since 2×114388338834122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11438833883413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 125901033 + ... + 125991855.
It is an arithmetic number, because the mean of its divisors is an integer number (305086625928).
Almost surely, 211438833883412 is an apocalyptic number.
11438833883412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11438833883412, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14644158044544).
11438833883412 is an abundant number, since it is smaller than the sum of its proper divisors (17849482205676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11438833883412 is a wasteful number, since it uses less digits than its factorization.
11438833883412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106129 (or 106127 counting only the distinct ones).
The product of its digits is 10616832, while the sum is 57.
Subtracting 11438833883412 from its reverse (21438833883411), we obtain a palindrome (9999999999999).
The spelling of 11438833883412 in words is "eleven trillion, four hundred thirty-eight billion, eight hundred thirty-three million, eight hundred eighty-three thousand, four hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •