Base | Representation |
---|---|
bin | 10000101001011101001… |
… | …010011101000001011111 |
3 | 11001100221000121001101111 |
4 | 100221131022131001133 |
5 | 122220430211302033 |
6 | 2233320231322451 |
7 | 145436663201653 |
oct | 20513512350137 |
9 | 4040830531344 |
10 | 1144024322143 |
11 | 4011a59a58aa |
12 | 165877520427 |
13 | 83b5b816a31 |
14 | 3d52a31aa63 |
15 | 1eb5a9147cd |
hex | 10a5d29d05f |
1144024322143 has 2 divisors, whose sum is σ = 1144024322144. Its totient is φ = 1144024322142.
The previous prime is 1144024322141. The next prime is 1144024322179. The reversal of 1144024322143 is 3412234204411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1144024322143 - 21 = 1144024322141 is a prime.
It is a super-2 number, since 2×11440243221432 (a number of 25 digits) contains 22 as substring.
Together with 1144024322141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1144024322141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572012161071 + 572012161072.
It is an arithmetic number, because the mean of its divisors is an integer number (572012161072).
Almost surely, 21144024322143 is an apocalyptic number.
1144024322143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144024322143 is an equidigital number, since it uses as much as digits as its factorization.
1144024322143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 1144024322143 its reverse (3412234204411), we get a palindrome (4556258526554).
The spelling of 1144024322143 in words is "one trillion, one hundred forty-four billion, twenty-four million, three hundred twenty-two thousand, one hundred forty-three".
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