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11455125002507 is a prime number
BaseRepresentation
bin1010011010110001101010…
…1010000001100100001011
31111120002200100122022200202
42212230122222001210023
53000140044000040012
640210224535522415
72261414450652344
oct246543252014413
944502610568622
1011455125002507
11371710047a61a
1213500b622940b
136512a1519874
142b86069890cb
1514ce92841cc2
hexa6b1aa8190b

11455125002507 has 2 divisors, whose sum is σ = 11455125002508. Its totient is φ = 11455125002506.

The previous prime is 11455125002429. The next prime is 11455125002509. The reversal of 11455125002507 is 70520052155411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11455125002507 - 230 = 11454051260683 is a prime.

Together with 11455125002509, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11455125002509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5727562501253 + 5727562501254.

It is an arithmetic number, because the mean of its divisors is an integer number (5727562501254).

Almost surely, 211455125002507 is an apocalyptic number.

11455125002507 is a deficient number, since it is larger than the sum of its proper divisors (1).

11455125002507 is an equidigital number, since it uses as much as digits as its factorization.

11455125002507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70000, while the sum is 38.

Adding to 11455125002507 its reverse (70520052155411), we get a palindrome (81975177157918).

The spelling of 11455125002507 in words is "eleven trillion, four hundred fifty-five billion, one hundred twenty-five million, two thousand, five hundred seven".