Base | Representation |
---|---|
bin | 100010001111111… |
… | …0101111111010101 |
3 | 2222002102022200202 |
4 | 1010133311333111 |
5 | 4323143321133 |
6 | 310011150245 |
7 | 40323011225 |
oct | 10437657725 |
9 | 2862368622 |
10 | 1149198293 |
11 | 53a768761 |
12 | 280a45385 |
13 | 1541181b9 |
14 | ac8a8085 |
15 | 6ad532e8 |
hex | 447f5fd5 |
1149198293 has 2 divisors, whose sum is σ = 1149198294. Its totient is φ = 1149198292.
The previous prime is 1149198233. The next prime is 1149198353. The reversal of 1149198293 is 3928919411.
It is a balanced prime because it is at equal distance from previous prime (1149198233) and next prime (1149198353).
It can be written as a sum of positive squares in only one way, i.e., 1140210289 + 8988004 = 33767^2 + 2998^2 .
It is a cyclic number.
It is not a de Polignac number, because 1149198293 - 212 = 1149194197 is a prime.
It is a super-3 number, since 3×11491982933 (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1149198203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574599146 + 574599147.
It is an arithmetic number, because the mean of its divisors is an integer number (574599147).
Almost surely, 21149198293 is an apocalyptic number.
It is an amenable number.
1149198293 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149198293 is an equidigital number, since it uses as much as digits as its factorization.
1149198293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 139968, while the sum is 47.
The square root of 1149198293 is about 33899.8273299437. The cubic root of 1149198293 is about 1047.4460356909.
The spelling of 1149198293 in words is "one billion, one hundred forty-nine million, one hundred ninety-eight thousand, two hundred ninety-three".
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