Base | Representation |
---|---|
bin | 11010001000010011100111… |
… | …110110001001000111101111 |
3 | 120001220020200210211212110102 |
4 | 122020103213312021013233 |
5 | 110030322212340424212 |
6 | 1044225311330301315 |
7 | 33130461406460606 |
oct | 3210234766110757 |
9 | 501806623755412 |
10 | 114920034701807 |
11 | 336873496a2655 |
12 | 10a8033312783b |
13 | 4c17bb3490a1a |
14 | 20542333c2a3d |
15 | d44501a1c5c2 |
hex | 6884e7d891ef |
114920034701807 has 2 divisors, whose sum is σ = 114920034701808. Its totient is φ = 114920034701806.
The previous prime is 114920034701699. The next prime is 114920034701831. The reversal of 114920034701807 is 708107430029411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114920034701807 - 212 = 114920034697711 is a prime.
It is a super-2 number, since 2×1149200347018072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114920034701887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57460017350903 + 57460017350904.
It is an arithmetic number, because the mean of its divisors is an integer number (57460017350904).
Almost surely, 2114920034701807 is an apocalyptic number.
114920034701807 is a deficient number, since it is larger than the sum of its proper divisors (1).
114920034701807 is an equidigital number, since it uses as much as digits as its factorization.
114920034701807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 338688, while the sum is 47.
The spelling of 114920034701807 in words is "one hundred fourteen trillion, nine hundred twenty billion, thirty-four million, seven hundred one thousand, eight hundred seven".
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