115015204319 has 2 divisors, whose sum is σ = 115015204320. Its totient is φ = 115015204318.

The previous prime is 115015204289. The next prime is 115015204321. The reversal of 115015204319 is 913402510511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115015204319 is a prime.

It is a super-3 number, since 3×115015204319³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 115015204321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115015204019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57507602159 + 57507602160.

It is an arithmetic number, because the mean of its divisors is an integer number (57507602160).

Almost surely, 2^115015204319 is an apocalyptic number.

115015204319 is a deficient number, since it is larger than the sum of its proper divisors (1).

115015204319 is an equidigital number, since it uses as much as digits as its factorization.

115015204319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 32.

The spelling of 115015204319 in words is "one hundred fifteen billion, fifteen million, two hundred four thousand, three hundred nineteen".