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1151130317 is a prime number
BaseRepresentation
bin100010010011100…
…1101101011001101
32222020001110221012
41010213031223031
54324142132232
6310120415005
740345306031
oct10447155315
92866043835
101151130317
11540868277
12281617465
131546436cc
14acc4c1c1
156b0d59b2
hex449cdacd

1151130317 has 2 divisors, whose sum is σ = 1151130318. Its totient is φ = 1151130316.

The previous prime is 1151130271. The next prime is 1151130319. The reversal of 1151130317 is 7130311511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 655667236 + 495463081 = 25606^2 + 22259^2 .

It is a cyclic number.

It is not a de Polignac number, because 1151130317 - 214 = 1151113933 is a prime.

Together with 1151130319, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1151130292 and 1151130301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1151130319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575565158 + 575565159.

It is an arithmetic number, because the mean of its divisors is an integer number (575565159).

Almost surely, 21151130317 is an apocalyptic number.

It is an amenable number.

1151130317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151130317 is an equidigital number, since it uses as much as digits as its factorization.

1151130317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 315, while the sum is 23.

The square root of 1151130317 is about 33928.3114375001. The cubic root of 1151130317 is about 1048.0326933282.

Adding to 1151130317 its reverse (7130311511), we get a palindrome (8281441828).

The spelling of 1151130317 in words is "one billion, one hundred fifty-one million, one hundred thirty thousand, three hundred seventeen".