11512145471 has 2 divisors, whose sum is σ = 11512145472. Its totient is φ = 11512145470.

The previous prime is 11512145387. The next prime is 11512145473. The reversal of 11512145471 is 17454121511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11512145471 - 2²² = 11507951167 is a prime.

It is a super-3 number, since 3×11512145471³ (a number of 31 digits) contains 333 as substring.

Together with 11512145473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11512145473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756072735 + 5756072736.

It is an arithmetic number, because the mean of its divisors is an integer number (5756072736).

Almost surely, 2^11512145471 is an apocalyptic number.

11512145471 is a deficient number, since it is larger than the sum of its proper divisors (1).

11512145471 is an equidigital number, since it uses as much as digits as its factorization.

11512145471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5600, while the sum is 32.

Adding to 11512145471 its reverse (17454121511), we get a palindrome (28966266982).

The spelling of 11512145471 in words is "eleven billion, five hundred twelve million, one hundred forty-five thousand, four hundred seventy-one".