Base | Representation |
---|---|
bin | 11010001011010010100010… |
… | …110101110111100001100000 |
3 | 120002121211211122212222012101 |
4 | 122023102202311313201200 |
5 | 110042202033032311112 |
6 | 1044503413335340144 |
7 | 33151336462103203 |
oct | 3213224265674140 |
9 | 502554748788171 |
10 | 115125035432032 |
11 | 3375628721a44a |
12 | 10ab4005521654 |
13 | 4c31323835c62 |
14 | 206011d6b593a |
15 | d499edede757 |
hex | 68b4a2d77860 |
115125035432032 has 24 divisors (see below), whose sum is σ = 226652956147800. Its totient is φ = 57562379902464.
The previous prime is 115125035432003. The next prime is 115125035432047. The reversal of 115125035432032 is 230234530521511.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 115125035431982 and 115125035432000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9999144 + ... + 18172312.
It is an arithmetic number, because the mean of its divisors is an integer number (9443873172825).
Almost surely, 2115125035432032 is an apocalyptic number.
It is an amenable number.
115125035432032 is a deficient number, since it is larger than the sum of its proper divisors (111527920715768).
115125035432032 is an equidigital number, since it uses as much as digits as its factorization.
115125035432032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8613358 (or 8613350 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 115125035432032 its reverse (230234530521511), we get a palindrome (345359565953543).
The spelling of 115125035432032 in words is "one hundred fifteen trillion, one hundred twenty-five billion, thirty-five million, four hundred thirty-two thousand, thirty-two".
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