1151253403 has 2 divisors, whose sum is σ = 1151253404. Its totient is φ = 1151253402.

The previous prime is 1151253401. The next prime is 1151253421. The reversal of 1151253403 is 3043521511.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (3043521511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1151253403 - 2¹ = 1151253401 is a prime.

Together with 1151253401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1151253401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575626701 + 575626702.

It is an arithmetic number, because the mean of its divisors is an integer number (575626702).

Almost surely, 2^1151253403 is an apocalyptic number.

1151253403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151253403 is an equidigital number, since it uses as much as digits as its factorization.

1151253403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1151253403 is about 33930.1253018612. The cubic root of 1151253403 is about 1048.0700460509.

Adding to 1151253403 its reverse (3043521511), we get a palindrome (4194774914).

The spelling of 1151253403 in words is "one billion, one hundred fifty-one million, two hundred fifty-three thousand, four hundred three".