Base | Representation |
---|---|
bin | 110101100111011010… |
… | …0100000010011100000 |
3 | 102000012020101020112011 |
4 | 1223032310200103200 |
5 | 3341301042120000 |
6 | 124521044442304 |
7 | 11214152344024 |
oct | 1531664402340 |
9 | 360166336464 |
10 | 115139020000 |
11 | 44914a7a984 |
12 | 1a3939a9394 |
13 | ab1c0b1a44 |
14 | 5803912384 |
15 | 2edd3602ba |
hex | 1aced204e0 |
115139020000 has 60 divisors (see below), whose sum is σ = 283259309256. Its totient is φ = 46055600000.
The previous prime is 115139019979. The next prime is 115139020019. The reversal of 115139020000 is 20931511.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 2858476 + ... + 2898475.
Almost surely, 2115139020000 is an apocalyptic number.
115139020000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
115139020000 is an abundant number, since it is smaller than the sum of its proper divisors (168120289256).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115139020000 is an frugal number, since it uses more digits than its factorization.
115139020000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5756981 (or 5756958 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 115139020000 its reverse (20931511), we get a palindrome (115159951511).
The spelling of 115139020000 in words is "one hundred fifteen billion, one hundred thirty-nine million, twenty thousand".
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