Base | Representation |
---|---|
bin | 10000110000011000000… |
… | …001100101101011101010 |
3 | 11002002002211102021202211 |
4 | 100300120001211223222 |
5 | 122331134300230002 |
6 | 2240545405515334 |
7 | 146122053050401 |
oct | 20603001455352 |
9 | 4062084367684 |
10 | 1151454305002 |
11 | 404368a33a01 |
12 | 1671ab872b4a |
13 | 84773c2b4b1 |
14 | 3da33004638 |
15 | 1ee42d65dd7 |
hex | 10c18065aea |
1151454305002 has 64 divisors (see below), whose sum is σ = 1895489395200. Its totient is φ = 522765550080.
The previous prime is 1151454304991. The next prime is 1151454305003. The reversal of 1151454305002 is 2005034541511.
It is not an unprimeable number, because it can be changed into a prime (1151454305003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24925558 + ... + 24971710.
It is an arithmetic number, because the mean of its divisors is an integer number (29617021800).
Almost surely, 21151454305002 is an apocalyptic number.
1151454305002 is a deficient number, since it is larger than the sum of its proper divisors (744035090198).
1151454305002 is a wasteful number, since it uses less digits than its factorization.
1151454305002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46511.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1151454305002 its reverse (2005034541511), we get a palindrome (3156488846513).
The spelling of 1151454305002 in words is "one trillion, one hundred fifty-one billion, four hundred fifty-four million, three hundred five thousand, two".
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