Base | Representation |
---|---|
bin | 1010011110001111011011… |
… | …1001011101101101011101 |
3 | 1111202210100002002211102002 |
4 | 2213203312321131231131 |
5 | 3002124003040043232 |
6 | 40253432002012045 |
7 | 2265622606205153 |
oct | 247436671355535 |
9 | 44683302084362 |
10 | 11514654612317 |
11 | 373a37938455a |
12 | 135b74a647025 |
13 | 656a9a68b15c |
14 | 2bb452b933d3 |
15 | 14e7c8b29b62 |
hex | a78f6e5db5d |
11514654612317 has 2 divisors, whose sum is σ = 11514654612318. Its totient is φ = 11514654612316.
The previous prime is 11514654612283. The next prime is 11514654612319. The reversal of 11514654612317 is 71321645641511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5805068615641 + 5709585996676 = 2409371^2 + 2389474^2 .
It is a cyclic number.
It is not a de Polignac number, because 11514654612317 - 214 = 11514654595933 is a prime.
Together with 11514654612319, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11514654612319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757327306158 + 5757327306159.
It is an arithmetic number, because the mean of its divisors is an integer number (5757327306159).
Almost surely, 211514654612317 is an apocalyptic number.
It is an amenable number.
11514654612317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11514654612317 is an equidigital number, since it uses as much as digits as its factorization.
11514654612317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 604800, while the sum is 47.
The spelling of 11514654612317 in words is "eleven trillion, five hundred fourteen billion, six hundred fifty-four million, six hundred twelve thousand, three hundred seventeen".
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