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11514654612317 is a prime number
BaseRepresentation
bin1010011110001111011011…
…1001011101101101011101
31111202210100002002211102002
42213203312321131231131
53002124003040043232
640253432002012045
72265622606205153
oct247436671355535
944683302084362
1011514654612317
11373a37938455a
12135b74a647025
13656a9a68b15c
142bb452b933d3
1514e7c8b29b62
hexa78f6e5db5d

11514654612317 has 2 divisors, whose sum is σ = 11514654612318. Its totient is φ = 11514654612316.

The previous prime is 11514654612283. The next prime is 11514654612319. The reversal of 11514654612317 is 71321645641511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5805068615641 + 5709585996676 = 2409371^2 + 2389474^2 .

It is a cyclic number.

It is not a de Polignac number, because 11514654612317 - 214 = 11514654595933 is a prime.

Together with 11514654612319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11514654612319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757327306158 + 5757327306159.

It is an arithmetic number, because the mean of its divisors is an integer number (5757327306159).

Almost surely, 211514654612317 is an apocalyptic number.

It is an amenable number.

11514654612317 is a deficient number, since it is larger than the sum of its proper divisors (1).

11514654612317 is an equidigital number, since it uses as much as digits as its factorization.

11514654612317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 604800, while the sum is 47.

The spelling of 11514654612317 in words is "eleven trillion, five hundred fourteen billion, six hundred fifty-four million, six hundred twelve thousand, three hundred seventeen".