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11515011106901 is a prime number
BaseRepresentation
bin1010011110010000110000…
…1001011000100001010101
31111202211020220220122001012
42213210030021120201111
53002130220320410101
640253531214542005
72265634465312031
oct247441411304125
944684226818035
1011515011106901
11373a541635185
12135b829b07905
13656b264a94b3
142bb4882711c1
1514e7ea097bbb
hexa790c258855

11515011106901 has 2 divisors, whose sum is σ = 11515011106902. Its totient is φ = 11515011106900.

The previous prime is 11515011106811. The next prime is 11515011106903. The reversal of 11515011106901 is 10960111051511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5823799695025 + 5691211411876 = 2413255^2 + 2385626^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11515011106901 is a prime.

Together with 11515011106903, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11515011106903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757505553450 + 5757505553451.

It is an arithmetic number, because the mean of its divisors is an integer number (5757505553451).

Almost surely, 211515011106901 is an apocalyptic number.

It is an amenable number.

11515011106901 is a deficient number, since it is larger than the sum of its proper divisors (1).

11515011106901 is an equidigital number, since it uses as much as digits as its factorization.

11515011106901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 32.

The spelling of 11515011106901 in words is "eleven trillion, five hundred fifteen billion, eleven million, one hundred six thousand, nine hundred one".