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115222230240197 is a prime number
BaseRepresentation
bin11010001100101101000100…
…000110101000101111000101
3120002222010201100001210200012
4122030231010012220233011
5110100300111420141242
61045020210053400005
733161350164250643
oct3214550406505705
9502863640053605
10115222230240197
1133793523151393
1210b0aa0b939005
134c3a54311b272
142064addd60193
15d4c2dbd16282
hex68cb441a8bc5

115222230240197 has 2 divisors, whose sum is σ = 115222230240198. Its totient is φ = 115222230240196.

The previous prime is 115222230240151. The next prime is 115222230240199. The reversal of 115222230240197 is 791042032222511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78600742878436 + 36621487361761 = 8865706^2 + 6051569^2 .

It is a cyclic number.

It is not a de Polignac number, because 115222230240197 - 210 = 115222230239173 is a prime.

Together with 115222230240199, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115222230240199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57611115120098 + 57611115120099.

It is an arithmetic number, because the mean of its divisors is an integer number (57611115120099).

Almost surely, 2115222230240197 is an apocalyptic number.

It is an amenable number.

115222230240197 is a deficient number, since it is larger than the sum of its proper divisors (1).

115222230240197 is an equidigital number, since it uses as much as digits as its factorization.

115222230240197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 115222230240197 in words is "one hundred fifteen trillion, two hundred twenty-two billion, two hundred thirty million, two hundred forty thousand, one hundred ninety-seven".